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A proton and an alpha - particle are acc...

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is

A

`1:2sqrt2`

B

`2:1`

C

`2sqrt2:1`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda_(p)/lambda_(alpha)=sqrt(q_(alpha)/q_(p)xxm_(alpha)/m_(p)`
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