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A positron and a proton are accelerated ...

A positron and a proton are accelerated by the same accelerating potential. Then the ratio of the associated wavelengths of the positron and the proton will be [`M`=mass of proton, `m`=mass of positron]

A

`M/m`

B

`sqrt(M/m)`

C

`m/M`

D

`sqrt(m/M)`

Text Solution

Verified by Experts

The correct Answer is:
B
`lambda=h/p,lambda=h/sqrt(2Vmq)`
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