Home
Class 12
PHYSICS
1.5 mW of 400 nm light is directed at a ...

1.5 mW of 400 nm light is directed at a photoelectric cell. If 0.1% of the incident photons produce photoelectrons, find the current in the cell.

A

`0.59 muA`

B

`1.16 muA`

C

`0.48 muA`

D

`0.79 muA`

Text Solution

Verified by Experts

The correct Answer is:
C

`L^(0)=q/t=(Ne)/t=(plambdae)/(hc)`
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE

    NARAYNA|Exercise NCERT BASED QUES.|26 Videos
  • DUAL NATURE

    NARAYNA|Exercise LEVEL-V|31 Videos
  • DUAL NATURE

    NARAYNA|Exercise LEVEL-II (C.W)|20 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NARAYNA|Exercise ASSERTION AND REASON|15 Videos
  • ELECTRIC CHARGES AND FIELDS

    NARAYNA|Exercise EXERCISE -4|43 Videos

Similar Questions

Explore conceptually related problems

A 100 W point source emits monochromatic light of wavelength 6000 A Q. 1.5 mW of 4000A light is directed at a photoelectric cell If 0.10 per cent of the incident photons produce photoelectrons, find current is the cell. [Given h=6.6xx10^(-34)Js , c=3xx10^(8)ms^(-1) and e=1.6xx10^(-19)C ]

A beam of light of wavelength 400nm and power 1.55 mW is directed at the cathode of a photoelectric cell. If only 10% of the incident photons effectively produce photoelectrons, then find current due to these electrons. (given hc=1240 eV-nm, e=1.6xx10^(-19)C )

Ultraviolet light of wavelength 66.26 nm and intensity 2 W//m^(2) falls on potassium surface by which photoelectrons are ejected out. If only 0.1% of the incident photons produce photoelectrons, and surface area of metal surface is 4 m^(2) , how many electrons are emitted per second?

Ultraviolet light of wavelength 300nn and intensity 1.0Wm^-2 falls on the surface of a photosensitive material. If one per cent of the incident photons produce photoelectrons, then the number of photoelectrons emitted per second from an area of 1.0 cm^2 of the surface is nearly

10^-3 W of 5000A light is directed on a photoelectric cell. If the current in the cell is 0.16muA , the percentage of incident photons which produce photoelectrons, is

10^(-3) W of 5000 Å light is directed on a photoelectric cell. If the current in the cell is 0.16 mA, the percentage of incident photons which produce photoelectrons, is

In photoelectric experiment set up, the maximum kinetic energy (k_("max")) of emitted photoelectrons was measured for different wavelength (lambda) of light used. The graph of k_("max") vs 1/(lambda) ​ was obtained as shown in first figure. In the same setup, keeping the wavelength of incident light fixed at l, the applied potential difference was varied and the photoelectric current was recorded. The result has been shown in graph in second figure. (a) Find lambda is Å (b) Taking the photo efficiency to be 2% (i.e. percentage of incident photons which produce photoelectrons) find the power of light incident on the emitter plate in the experiment. [Take hc = 12400 eV Å ]

Ultraviolet light of wavelength 350 nm and intensity 1 W//m^2 is directed at a potassium surface having work function 2.2 eV (ii) if 0.5 percent of the incident photons produce photoelectric effect, how many photoelectrons per second are emitted from the potassium surface that has an area 1 cm^2 . E_("kmax") =1.3 eV, n= 8.8 xx 10^(11)("photo electron")/("second") or r =(Nhv)/t =nhv

How will photoelectric current through a photoelectric cell change on increasing the intensity of the light incident on the cell ?

A : On increasing the intensity of light , the number of photoelectrons emitted is more . Also the kinetic energy of each photo increases but the photoelectric current is constant R : Photoelectric current is independent of intensity but increases with increasing frequency incident radiation

NARAYNA-DUAL NATURE-LEVEL-III
  1. An electron accelerated under a p.d. Of V volt has a certain wavelengt...

    Text Solution

    |

  2. The graph between the stopping potential (V(0)) and ((1)/(lambda)) is...

    Text Solution

    |

  3. For certain photosensitive material, a stopping potential of 3.0 V is ...

    Text Solution

    |

  4. A graph regarding photoelectric effect is shown between the maximum k...

    Text Solution

    |

  5. Light described at a place by the equation E = (100V//M) xx [sin (5 xx...

    Text Solution

    |

  6. The electric field associated with a light wave is given by E= E0 sin...

    Text Solution

    |

  7. A photocell is illuminated by a small bright source places 1 m away w...

    Text Solution

    |

  8. Photoelectric effect supports quantum nature of light because (a) th...

    Text Solution

    |

  9. If the wavelength of light in an experiment on photoelectric effect is...

    Text Solution

    |

  10. Intensity and frequency of incident light both are doubled. Then, wha...

    Text Solution

    |

  11. In which of the following cases the heavier of the two particles has a...

    Text Solution

    |

  12. When a monochromatic point source of light is at a distance of 0.2 m...

    Text Solution

    |

  13. In a photoelectric experiment, the wavelength of the incident light is...

    Text Solution

    |

  14. Photoelectric threshold of silver is lamda=3800A. Ultraviolet light of...

    Text Solution

    |

  15. Photoelectric threshold of silver is lamda=3800A. Ultraviolet light of...

    Text Solution

    |

  16. Photoelectric threshold of silver is lamda=3800A. Ultraviolet light of...

    Text Solution

    |

  17. A 100 W point source emits monochromatic light of wavelength 6000 A ...

    Text Solution

    |

  18. A 100 W point source emits monochromatic light of wavelength 6000 A ...

    Text Solution

    |

  19. 1.5 mW of 400 nm light is directed at a photoelectric cell. If 0.1% of...

    Text Solution

    |

  20. Statement - 1 : When ultraviolet light is incident on a photocell , it...

    Text Solution

    |