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When a centimeter thick surface is illum...

When a centimeter thick surface is illuminated with light of wavelength `lamda`, the stopping potential is V. When the same surface is illuminated by light of wavelength `2lamda`, the stopping potential is `(V)/(3)`. Threshold wavelength for the metallic surface is

A

`(4lambda)/3`

B

`4lambda`

C

`6lambda1`

D

`(8lambda)/3`

Text Solution

Verified by Experts

The correct Answer is:
B
`(hC)/lambda=phi+eV`..(i)
`(hC)/(2lambda)=phi+(eV)/3`..(ii)
`3xxII-IrArr (3/2-1)(hc)/lambda=2phi rArr phi=(hc)/(4lambda)`
`therefore lambda_(th)=4lambda`
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