A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The ratio of the de Broglie wavelength . The ratio of the de Broglie wavelength of the particle `lambda , _(1) // lambda_(2)` is

Options

A. `m_(1)/m_(2)`
B. `m_(2)/m_(1)`
C. `1:1`
D. `sqrt(m_(2)/m_(1))`

Answer

C

Explanation

`lambda=h/p` and from conservation of linear momentum both particles will have same magnitude of linear momentum after decay.