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A proton and an electron are accelerated...

A proton and an electron are accelerated by the same potential difference, let `lambda_(e)` and `lambda_(p)` denote the de-Broglie wavelengths of the electron and the proton respectively

A

`lambda_(e)=lambda_(p)`

B

`lambda_(e) lt lambda_(p)`

C

`lambda_(e) gt lambda_(p)`

D

`lambda_(e)` and `lambda_(p)` depends on the accelerating potential difference.

Text Solution

Verified by Experts

The correct Answer is:
C

`lambda=h/sqrt(2mKE)=h/sqrt(2mqV).`As `q` and `V` are same for both `lambda prop 1/sqrtm rArr lambda_(e) gt lambda_(p)`
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