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If we assume that perptraing power of an...

If we assume that perptraing power of any radiation/particle is inversely proportional to its de-Broglie wavelength of the particle then:

A

a proton and an `alpha` particle after getting accelerated through same potential difference will have equal penetration power.

B

penetrating power of `alpha ` particle will be greater than that of proton which have been accelerated by same potential difference.

C

proton's penetrating power will be less than penetrating power of an electron which has been accelerated by the same potential difference.

D

penetrating powers can not be compared as all these are particles having no wavelength or wave nature.

Text Solution

Verified by Experts

The correct Answer is:
B
`lambda=h/sqrt(2mq.V)`
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