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If accelerating potential of an alpha pa...

If accelerating potential of an alpha particle is doubled than its new debrolgie wavelength becomes

A

`1/sqrt2`times of initial

B

`sqrt2`times of initial

C

`1/2`times of initial

D

`2`times of initial

Text Solution

Verified by Experts

The correct Answer is:
A
`lambda alpha1/sqrtV`
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