Home
Class 12
PHYSICS
Ultraviolet light of wavelength 800 A an...

Ultraviolet light of wavelength `800 A` and `700 A` when allowed to fall on hydrogen atoms in their ground states is found to liberate electrons with kinetic energies `1.8eV` and `4.0eV`, respectively. Find the value of Planck's constant.

A

`6.57xx10^(-34) Js`

B

`6.63xx10^(-34) Js`

C

`6.66xx10^(-34) Js`

D

`6.77xx10^(-34) Js`

Text Solution

Verified by Experts

The correct Answer is:
A

`(hc)/lambda=w+eV_(0)`
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE

    NARAYNA|Exercise LEVEL-I (H.W)|7 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NARAYNA|Exercise ASSERTION AND REASON|15 Videos
  • ELECTRIC CHARGES AND FIELDS

    NARAYNA|Exercise EXERCISE -4|43 Videos

Similar Questions

Explore conceptually related problems

Ultraviolet light of wavelengths lambda_(1) and lambda_(2) when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energy 1.8 eV and 4.0 eV respectively. Find the value of (lambda_(1))/(lambda_(2)) .

U.V. light of wavelenght 800Å & 700Å falls on hydrongen atoms in thir ground state & liberates electrons with kinetic energy 1.8eV and 4eV respectively . Calculate planck 's constant.

U.V . light of wavelength 800A^(@)&700A^(@) falls on hydrogen atoms in their ground state & liberates electrons with kinetic energy 1.8eV and 4eV respectively. Calculate planck's constant.

Ultraviolet light of wavelength lambda_(1) and lambda_(2) (with lambda_(2) gt lambda_(1) ) when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energies E_(1) and E_(2) respectively. The value of the planck's constant can be found from the relation

The total energy of the electron in the hydrogen atom in the ground state is -13.6 eV. Which of the following is its kinetic energy in the first excited state?

A photon of energy 10.5eV is allowed to interact with a hydrogen atom in its ground state. Then :

The total energy of the electron in the hydrogen atom in the ground state is - 13.6 eV . The KE of this electron is.

(a) A gas of hydrogen atoms is their ground state is bombarded by electrons with kinetic energy 12.5 ev. What emitted wavelengths would you expect to see? (b) What if the electrons were replaced by photons of same anergy?.

An electron with kinetic energy =E eV collides with a hydrogen atom in the ground state. The collision will be elastic

Total energy of an electron in the hydrogen atom in the ground state is -13.6 eV. The potential energy of this electron is

NARAYNA-DUAL NATURE-LEVEL-II (H.W)
  1. When a metal surface is illuminated by a monochromatic light of wave-l...

    Text Solution

    |

  2. Ultraviolet light of wavelength 800 A and 700 A when allowed to fall ...

    Text Solution

    |

  3. In a photoelectric effect experiment, photons of energy 5eV are incide...

    Text Solution

    |

  4. The number of photons emitted per second by a 62W source of monochroma...

    Text Solution

    |

  5. Photons of frequencies 2.2xx10^(15) Hz and 4.6xx10^(15) Hz are inciden...

    Text Solution

    |

  6. If stopping potentials corresponding to wavelengths 4000A and 4500A ar...

    Text Solution

    |

  7. In a photoelectric experiment anode potential is ploted against plate ...

    Text Solution

    |

  8. An electron moves with a speed of sqrt3/2c. Then its mass becomes…. Ti...

    Text Solution

    |

  9. Photons of energy 2.0eV fall on a metal plate and release photoelectro...

    Text Solution

    |

  10. A proton when accelerated through a p.d of V volt has wavelength lambd...

    Text Solution

    |

  11. The momentum of photon of electromagnetic radiation is 3.3xx10^(-29)kg...

    Text Solution

    |

  12. If the energy of a particle is reduced to one fourth, then the percent...

    Text Solution

    |

  13. The de Broglie wavelength associated with an electron of velocity 0.3c...

    Text Solution

    |

  14. The two lines A and B in fig. show the photo electron of de Broglie wa...

    Text Solution

    |

  15. The uncertainity in the position of a particle is equal to the de-Brog...

    Text Solution

    |

  16. If the uncertainty in the position of proton is 6xx10^-8m, then the mi...

    Text Solution

    |

  17. From Davisson-Germer experiment an alpha particle and a proton are acc...

    Text Solution

    |