Photons of frequencies 2.2xx10^(15) Hz a...

Photons of frequencies `2.2xx10^(15) Hz` and `4.6xx10^(15) Hz` are incident on a metal surface. The corresponding stopping potentials were found to be `6.6V` and `16.5V` respectively. Given `e=1.6xx10^(-19) c`, the value of universal planck's constant is

`6.6xx10^(-34) Js`

`6.7xx10^(-34) Js`

`6.5xx10^(-34) Js`

`6.8xx10^(-34) Js`

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The correct Answer is:

`hv=w+eV_(0)`

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