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When two capacitors are joined in series...

When two capacitors are joined in series the resultance capacity is `2.4 muF` and when the same two are joined in parallel the resultant capacity is `10 mu F`. Their individual capacities are.

A

`7 mu F,3 mu F`

B

`1 mu F,9 mu F`

C

`6 mu F,4 mu F`

D

`8 mu F,2 mu F`

Text Solution

Verified by Experts

The correct Answer is:
C
`C_(S)=(C_(1)C_(2))/(C_(1)+C_(2)) ,C_(1)+C_(2)=C_(P)`.
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