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The cross section of a cable is shown i...

The cross section of a cable is shown in fig. The inner conductor has a radius of `10 mm` and the dielectric has a thickness of `5 mm`. The cable is `8 km`. Long. Then the capacitance of the cable is `[log_(e) 1.5 =0.4]`..

A

`3.8 mu F`

B

`1.1 mu F`

C

`4.8 xx 10^(-10) mu F`

D

`3.3 mu F`

Text Solution

Verified by Experts

The correct Answer is:
B
`C=( epsilon_(o)2 pi l)/(ln(b//a))`.= `1.1 mu F`
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