Equipotential surfaces

Options

A. are closer in regions of large electric fields compared to regions of lower electric fields
B. will be more crowded near sharp edges of a conductor.
C. will be more crowded near regions of large charge densities
D. will aways be equally spaced

Answer

A, B, C

Explanation

`E=-(dV)/(dr) or dr=-(dV)/(E)`
For a fixed value of `dV, dr prop - (1)/( E)` , which implies that spacing between two equipotential surfaces decreases as `E` increases. So, equipotential surfaces are closer in regions of large electric fields. At sharp deges `a=of` conductor, charge density is more. So, electric field is large and hence the equipotential surfaces will be more crowded.