A parallel plate capacitor was lowered into water in a horizontal position, with water filling up the gap between the plates. The distance between the plates is `d`. Then a constant voltage `V` was applied to the capacitor. Find the water pressure increment in the gap. Dielectric constant of water is `k`.

Options

A. `Delta p=(epsilon_(0)(k-1)V^(2))/(2d^(2))`
B. `Delta p=(epsilon_(0)k(k-1)V^(2))/(2d^(2))`
C. `Delta p=(epsilon_(0)(k-1)V^(2))/(4d^(2))`
D. `Delta p=(2epsilon_(0)(k-1)V^(2))/(d^(2))`

Answer

B

Explanation

`Delta P=(Delta F)/(A) F=(Q^(2))/(A epsilon_(0))`.