A capacitor of capacitance C is given a charge Q. At `t=0`,it is connected to an uncharged of equal capacitance through a resistance R. Find the charge on the second capacitor as a function of time.

Options

A. `Q(1-e^(-(2t)/(RC)))`
B. `(Q)/(2)(1-e^(-(2t)/(RC)))`
C. `(Q)/(2)(1-e^(-(t)/(RC)))`
D. `Q(1-e^(-(t)/(RC)))`

Answer

B

Explanation

At any instance charges on capacitors will be as shown

Applying `KVL`, we get
`(q)/(C)=((Q-q))/(C)+iR=0 and i=(dq)/(dt)`.