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In the fig. shown the circuit is in stea...

In the fig. shown the circuit is in steady state.

If the battery is disconnected give the capacitor charge as a function of time.

A

`Q=200 e^(-3t//10)`

B

`Q=200e^(-3t//1000)`

C

`Q=200 e^(-3t)`

D

`Q = 100 e^(-3000 t)`

Text Solution

Verified by Experts

The correct Answer is:
B
`q =q_(0) e^(-t//r) q_() = 200 muc tau = RC`
`R` is effective resistance across capacitor.
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