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In the fig. shown the circuit is in stea...

In the fig. shown the circuit is in steady state.

How long does it take for the capacitor to discharge until the potential difference across it becomes `1 V` ?

A

`1766.1 mu s`

B

`333.34 mu s`

C

`1000 mu s`

D

`333.34 s`

Text Solution

Verified by Experts

The correct Answer is:
C
`q=q_(0) e^(-t//tau) V=V_(0) e^(-t//tau) i=20 e^((-3t)/(1000))t=1000s`.
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