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In the circuit diagram shown here seven capacitors are connected to a source of emf `E`. Initially, the switch `S` is closed and steady state attained. Now, the potential difference between the points 'a' and 'b' is `4` volt. Now, answer the following :
.
The emf `E` of the battery is :

A

46 V

B

26 V

C

14 V

D

10 V

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(eff)=(120)/(46)muC`
Charge supplied by battery (i.e)
`C_(5)=120 muC`
`:. E=46 V Q_(fg)=45 muC Q_(10)=75 muC`.
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