The resistance of a decinormal solution of a salt occupying a volume between two platinum electrodes which are 1.80 cm apart and 5.4 `cm^(2)` in area was found to be 50 `omega` calculate the equilvalent conductance of the solution

Options

A. 66.66
B. 64.6
C. 60.62
D. 6567

Explanation

We know that equivalent condductance
`wedge_(eq)=(1000 xx "conductance" xx "cell constant" )/("normality")`

Given conductance `=(1)/("resistance")=1/50 omega^(-1)=0.02 S`
cell constant `=(1)/(a)=("distance")/("area")=(1.80)/(5.40)=1/3 cm^(-1)`
Normality =0.1 N

`=(14000xx0.02)/(0.1)xx1/3`
`=66.66 S cm^(2) "equivalent"^(-1)`