In an aqueous solution `AgNO_(3)` and `CuSO_(4)` are connected in series if Ag deposited at cathode is 1.08 g then Cu deposited is

Options

A. 0.532 g
B. 0.181 g
C. 0.264 g
D. 0.315 g

Explanation

To solve the problem of determining the mass of copper deposited when 1.08 g of silver is deposited, we can use Faraday's laws of electrolysis. Here’s the step-by-step solution:

### Step 1: Understand the relationship between the deposited masses
When two electrolytic cells are connected in series, the same amount of charge passes through both cells. According to Faraday's laws, the mass of a substance deposited at an electrode is directly proportional to the quantity of electricity that passes through the cell.

### Step 2: Write the formula for the ratio of deposited masses
The ratio of the masses of the metals deposited can be expressed as:
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