The values of `wedge_(m)^(oo)` for`NH_(4)Cl,NaOH,` and `NaCl` are, respectively, `149.74,248.1`,and `126.4 ohm^(-1)cm^(2)eq^(-1)`. The value of `wedge_(eq)^(oo)NH_(4)OH` is

Options

A. 371.44
B. 271.44
C. 71.44
D. cannot be predicte from given data

Answer

D

Explanation

`wedge_(eq)^(prop)(NH_(4)OH)=wedge_(eq)^(infty)(NH_(4)CI)+wedge_(eq)^(prop)(NaOH)-wedge_(eq)^(infty)(NaCI)`
`=(149.74+248.1 - 126.4)`
`=271.44 omega^(-1) cm^(2) equiv^(-1)`