The molar conductivities of KCl, NaCl and `KNO_(3)` are 152,128 and `111" S cm"^(2) mol^(-1)` respectively. What is the molar conductivity of `NaNO_(3)` ?

Options

A. `101 s cm^(2) mol^(-1)`
B. `87 s cm^(2) mol^(-1)`
C. `-101 s cm^(2) mol^(-1)`
D. `-391 s cm^(2) mol^(-1)`

Answer

B

Explanation

`NaCI + KNO_(3) rarr NaNO_(3)+KCI` Molar conductivity of KCI =`152 cm^(2) mol^(-1)`
Molar conductivity of NaCI =128 S `cm^(2) mol^(-1)`
Difference =`24 cm "Sd"^(2) "mol"^(-1)`
,Molar conductivity of `KNO_(3)=111`
Molar conductivities of `NaNO_(3) =111-24=87 S cm^(3) "mol"^(-1)`