Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10mA` current. The time required to liberate `0.01mol` of `H_(2)` gas at the cathode is `(1F=96500C mol ^(-1))`

Options

A. `9.65xx10^(4)`s
B. `19.3 xx10^(4)` s
C. `28.95 xx 10^(4)`s
D. `38.6xx10^(4)` s

Answer

B

Explanation

`2H_(2)O+2e^(-) rarr H_(2) 2OH^(-)`
for 0.01 mole of `H_(2)` 0.02 mole of electron are consumed charge required `=0.02 xx96500 C=I xx t`
Time required `=(0.02 xx96500)/(10 xx10^(-3))=19.3xx10^(4)` S