The electrode pptenticals for
` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) `
and ` Cu^+ (aq) + e^- rarr Cu (s)`
are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(cu^(2+)//Cu)^@` will be.

Options

A. 0.150 V
B. 0.500 V
C. 0.325 V
D. 0.650 V

Answer

D

Explanation

`triangle G_(3) = triangleG_(1) +triangle G_(2)`
`-2 FE_(3)^(@) =- 1 Fxx0.015 +(-1 Fxx 0.50)`
`-2 FE_(3)^(@)=- 0.15 F-0.05 F`
`rarr -2FE_(3)^()=-F(0.15 +0.50)`
`therefore E_(3)^(@)=(0.65)/(2) =0.325 V`