`E^(@)` values of `Mg^(2+)//Mg "is" -2.37 V` of `Zn^(2+)//Zn` is `-0.76 V` and `Fe^(2+)//Fe:-0.44 V`
which of the following statement is correct ?

Options

A. Zn will reduce `Fe^(2+)`
B. Zn will reduce `Mg^(2+)`
C. Mg oxidises Fe
D. Zn oxidises Fe

Answer

A

Explanation

Higher the negative value of `E^(@)` more is the reducing power the order of `E^(@)` values (negative value ) is
`-2.37 gt -0.76 gt -0.44`
`therefore` Mg can reduce both `Zn^(2+)` and `Fe^(2+)` Zn can reduce `Fe^(2+)` but not `Ng^(2+)` Fe cannot reduce Mg and Zn but can oxidse them