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The potential of the following cell is ...

The potential of the following cell is 0.34 V at `25^(@)C` calculate the standard reduction potential of the copper half cell
`Pt|H_(2)(1 atm)| H^(+)(1 M)||Cu^(2+)(1 M)|Cu`

A

`-3.4 V`

B

`+3.4 V`

C

`-0.34 V`

D

`+0.34 V`

Text Solution

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The correct Answer is:
To calculate the standard reduction potential of the copper half-cell in the given electrochemical cell, we can follow these steps: ### Step 1: Identify the components of the cell The cell is represented as: \[ \text{Pt} | \text{H}_2 (1 \text{ atm}) | \text{H}^+ (1 \text{ M}) || \text{Cu}^{2+} (1 \text{ M}) | \text{Cu} \] Here, the left side (anode) is the hydrogen half-cell, and the right side (cathode) is the copper half-cell. ### Step 2: Understand the cell potential The overall cell potential (\(E_{\text{cell}}\)) is given as 0.34 V at standard conditions (1 M concentration for ions and 1 atm pressure for gases). ### Step 3: Write the formula for cell potential The cell potential can be expressed using the standard reduction potentials of the cathode and anode: \[ E_{\text{cell}} = E_{\text{cathode}} - E_{\text{anode}} \] ### Step 4: Identify the anode and cathode - **Anode (oxidation)**: Hydrogen half-cell, where the standard reduction potential (\(E_{\text{anode}}\)) for the hydrogen electrode is defined as 0 V. - **Cathode (reduction)**: Copper half-cell, where we need to find the standard reduction potential (\(E_{\text{cathode}}\)). ### Step 5: Substitute known values into the equation Substituting the known values into the equation: \[ 0.34 \, \text{V} = E_{\text{copper}} - 0 \, \text{V} \] ### Step 6: Solve for the standard reduction potential of copper From the equation: \[ E_{\text{copper}} = 0.34 \, \text{V} \] ### Conclusion The standard reduction potential of the copper half-cell is: \[ E_{\text{copper}} = 0.34 \, \text{V} \] ---

To calculate the standard reduction potential of the copper half-cell in the given electrochemical cell, we can follow these steps: ### Step 1: Identify the components of the cell The cell is represented as: \[ \text{Pt} | \text{H}_2 (1 \text{ atm}) | \text{H}^+ (1 \text{ M}) || \text{Cu}^{2+} (1 \text{ M}) | \text{Cu} \] Here, the left side (anode) is the hydrogen half-cell, and the right side (cathode) is the copper half-cell. ...
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