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Given for Sn^(4+)//Sn^(2+) standard red...

Given for `Sn^(4+)//Sn^(2+)` standard reduction potential is 0.15 V and for `Au^(3+) //Au` standard reduction potential is 1.5 V for the reaction
`3 Sn^(2)+2 Au^(3+) rarr 3Sn^(4+)+2ASu`
The value of `E_(cell)^(@)` is

A

`+1.35`

B

`+2.55`

C

`-1.35`

D

`-2.55`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(cell)^(2)=E_(cathode)^(2) -E_(anode)^(@) =1.5 -0.15 =1.35 V`
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