The ionic conductance of `Ba^(2+)` and `CI^(-)` are respectively 127 and 76 `omega^(-1) cm^(2)` of `BaCI_(2)` at infinite dilution will be

Options

A. 139.5
B. 203
C. 279
D. 101.5

Answer

B

Explanation

The equivelnt weight of `BaCI_(2)=("Molecular weight")/(2)`
`lambda_(m)^(infty) "for" BaCI_(2) = lambda_(m)^(infty) Ba^(2+) +2 lambda_(m)^(infty) CI^(-)`
`therefore lambda_(eq)^(infty) for BaCI_(2) =1//2 lambda_(m)^(infty) Ba^(2+) + lambda_(m)^(infty) CI^(-)`
`=127//2+76 =139.5 "ohm"^(-01) cm^(-2)`