When 1 F of electricity is passed through acidulated water `O_(2)` evolved is

Options

A. `11.2 dm^(3)`
B. `5.6 dm^(3)`
C. `22.4 dm^(3)`
D. `1.0 dm^(3)`

Answer

B

Explanation

Write balance reaction for electrolysis of water and use faraday 's law and mole concept
`2H_(2) O rarr 4H^(+) +2O^(2-)`
at cathode `4H^(+) +4e^(-) rarr 2H_(2)`
At anode `2O_(2-) - 4e^(-) rarr O_(2)`
`therefore` 4 faraday of charge liberates =1 mol `=22.4 dm^(3) O_(2)`
at anode `2O^(2-) - 4e^(-) rarr O_(2)`
`therefore` 4 faraday of charge liberates = 1 mol `= 22.4 dm^(3) O_(2)`
`therefore` 1 faraday of charge liberates =`(22.4)/(4)xx1=5.6 dm^(3) O_(2)`