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The emf of a galvanic cell with electrod...

The emf of a galvanic cell with electrode potential of `Zn^(2+)//Zn=-0.76 V` and that of `Cu^(2+)//Cu=+0.34 V` is

A

`+ 0.34 V`

B

`+0.76 V`

C

`-1.1 v`

D

`+1.1 V`

Text Solution

Verified by Experts

The correct Answer is:
B
Because the value of `E_(red)^(@)` is lesser for Zn hence it will act as anode and Cu as cathode in the galvanic cell
`E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@)=(0.34)-(-0.76)=1.1 V`
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