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CH(3)-CH(2)-Br on treatment with LiAlH(4...

`CH_(3)-CH_(2)-Br` on treatment with `LiAlH_(4)` gives ethane gas while `(CH_(3))_(3)C-Br` on same treatment gives `H_(2)` gas because

A

the former is `S_(N)2` and later is E2 reaction

B

the former is E2 and later is `S_(N)2` reaction

C

the former is `S_(N)1` and later is E2 reaction

D

the former is E2 and later is `S_(N)1` reaction

Text Solution

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The correct Answer is:
A

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