Tertiary alkyl halide are practially inert to substitution by `SN^(2)` mechanism because of-

Options

A. steric hindrance
B. inductive effect
C. instability
D. insolubility

Answer

A

Explanation

In `S_(N)2` reaction, nucleophile and alkyl halide react in one step.

Thus, tertiary carbon is under steric hndrance due to presence of three bulky alkyl groups thus reaction does not take place unit `(C-Br)` bond breaks
`R-overset(R)overset(|)underset(R)underset(|)C-Br overset("Slow")rarr R-overset(R)overset(|)underset(R)underset(|)(C^(o+))+Br^(-)`