Of the isomeric haexanes, the isomers that give the minimum and maximum number of monochloro derivatives are, respectively,

Options

A. 3-methylpentane and 2, 3-dimethylbutane
B. 2, 3-dimethylbutane and n-hexane
C. 2,2,-dimethylbutane and 2-methylpentane
D. 2,3-dimethylbutane and 2-methylpentane

Answer

D

Explanation

The possible isomers of hexane are

Out of these structure (iii) and (i) have respectively minimum an maximum number of monochloro derivatives. For structure (iii),

Only 2 monochloro derivtives (minimum) are possible.
For structure (i),

5 monochloro derivatives (maximum ) are possible.