In a hydrogen atom, electron revolves in a circular orbit of radis 0.53 Å with a velocity of `2.2xx10^(6)ms^(-1)` and angle between its position and velocity is `30^(@)`. If the mass of electron is `9xx10^(-31)kg`. Find its angular momentum.

Options

A. `5.247xx10^(-37)kg-m^(2)s^(-1)`
B. `2.345xx10^(-30)kg-m^(2)s^(-1)`
C. `6.372xx10^(-36)kg-m^(2)s^(-1)`
D. None of these

Answer

A

Explanation

Given, `r = 0.53Å=0.53xx10^(-10)m,`
`m=9xx10^(-31)kg, v=2.2xx10^(6)ms^(-1), theta=30^(@), L=?`
`L=mvr sin theta`
`=9xx10^(-31)xx2.2xx10^(6)xx0.53xx10^(-10)xx0.53xx10^(-10)xxsin 30^(@)`
`=5.247xx10^(-35)kg-m^(2)s^(-1)`