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Total kinetic energy of a rolling solid ...

Total kinetic energy of a rolling solid spher of mass m with velocity is

A

`(7)/(10)Mv^(2)`

B

`(5)/(6)Mv^(2)`

C

`(7)/(5)Mv^(2)`

D

`(10)/(7)Mv^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Total kinetic energy = Translational KE + Rotational KE
`=(1)/(2)mv^(2)+(1)/(2)l omega^(2)`
`=(1)/(2)mv^(2)+(1)/(2)((2)/(5)mR^(2))((v)/(R))^(2)`
`{{:(because" moment of inertia of sphere about its centre of mass"),(" "l=(2)/(5)mR^(2)):}}`
`" "=(1)/(2)mv^(2)+(1)/(5)mv^(2)=(7)/(10)mv^(2)`
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