Consider a body, shown in the figure, consisting of two identical balls, each of mass M connected by a light rigid rod. If an impulse J = Mv is imparted to the body at one of its ends, what would be its angular velocity ?

Options

A. v/L
B. 2v/L
C. v/3L
D. v/4L

Answer

A

Explanation

Let `omega` be the angular velocity of the rod. Applying, Angular impulse = Change in angular momentum about centre of mass of the system

`J.(L)/(2)=l_(c)omega`
`therefore" "(Mv)((L)/(2))=(2)((ML^(2))/(4))omega rArr omega=(v)/(L)`