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Let ABCD be a parallelogram whose diagon...

Let ABCD be a parallelogram whose diagonals intersect at P and O be the origin, then `OA+OB+OC+OD` equals

A

`OP`

B

`2 OP`

C

`3 OP`

D

`4 OP`

Text Solution

Verified by Experts

The correct Answer is:
D
Since, the diagonals of a paralelogram bisect each other. Therefore, P is the middle point of AC and BD both.
`:." "OA + OC = 2 OP" and "OB+OD=2OP`
`rArr" "OA+OB+OC+OD=4 OP`
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