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In Duma's method for estimation of nitro...

In Duma's method for estimation of nitrogen. `0.25 g `of an organic compound gave `40mL` of nitrogen collected at `300K` temperature of `725 mm` pressure. If the aqueous tension at `300K` is `25 mm`, the percentage of nitrogen in the compound is

A

`17.36`

B

`18.20`

C

`16.76`

D

`15.76`

Text Solution

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The correct Answer is:
C
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In Dumas’ method for estimation of nitrogen, 0.3g of an organic compound gave 50mL of nitrogen collected at 300K temperature and 715mm pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at 300K=15 mm)

In Dumas' method for estimation of nitrogen, 0.3 g of an organic compound released 50 mL of nitrgen gas collected under 715 mm Hg and at 300 K . If aqueous tension at 300 K is 15 mm Hg , calculate the percentage composition of nitrogen in the organic compound. Strategy: Step 1 . Calculate the volume of N_(2) gas at STP//NTP using combined gas equation. Step 2 . Find the munber of moles of N_(2) gas: n_(N_(2)) = ("Volume of "N_(2) "gas at" NTP)/(22400 mL mol^(-1)) Step 3 . Find the mass of N_(2) gas: m_(N_(2)) = n_(N_(2)) xx Molar mass of N_(2) Step 4 . Find the % of N_(2) gas % N = ("Mass of nitrogen")/("Mass of organic compound") xx 100% or use Eq. (13.7) where steps (2) to (4) are combined.

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