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The displacement of a particle moving...

The displacement of a particle moving in a circular path is given by `theta = 3 t^(2) + 0.8 ,` where ` theta ` is in radian and t is in seconds . The angular velocity of the particle at t=3 sec . Is

A

18 rad/s

B

15 rad/s

C

12 rad /s

D

8 rad /s

Text Solution

Verified by Experts

The correct Answer is:
A
`theta = 3 t^(2) + 0.8 " " therefore omega = ( d theta)/( dt) = 3xx2t = 6 t`
`therefore `At time t=3 `, omega = 6x3 = 18 rad//s`
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Knowledge Check

  • If the equation for the displacement of a particle moving on a circle path is given by, theta = 2t^(2)+0.5 where, theta is in radian and t is in second, then the angular velocity of the particle after 2 s is

    A
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    B
    `12 rad s^(-1)`
    C
    `24 rad s^(-1)`
    D
    `36 rad s^(-1)`

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    8 `rad//s`
    B
    12`rad//s`
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    24`rad//s`
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    36`rad//s`

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    D
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