A car is moving on a circular track ...

A car is moving on a circular track of diameter 72 m with a speed of 6 m/s . It is acclereration at the rate of `sqrt(3) m//s^(2)` If the mass of the car is 1000 kg , the net force acting on the car is :

1000 N

2000 N

`1000 sqrt(3) N`

`(1000)/( sqrt(3))N`

Text Solution

Verified by Experts

The correct Answer is:

The resultant acceleration of the car
` a= sqrt ( a_(R )^(2) +a_(T ) ^2)a_(T ) = sqrt(3) m//s ^(2)`
` and a_(R ) = (v^2)/(R ) = (6xx6)/(36) " " therefore a_(R ) ^(2) =1`
` therefore a= sqrt( 1+4)= 2 m//s^(2)`
` therefore `Force `= ma = 1000xx2 = 2000 N`

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