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The K.E (K ) of a particle moving a...

The K.E (K ) of a particle moving along a circle r depends upon the distance covered (s) as ` K= as ^(2)` The centripetal force acting on the particle is given by

A

`2as`

B

`2as^(2)`

C

`(2as^2)/(r )`

D

`(2 ar )/( s^2)`

Text Solution

Verified by Experts

The correct Answer is:
C
K.E `=(1)/(2) mv^(2) = as^(2)`
C.P force `(F ) =(mv^2)/(r ) =(2((1)/(2)mv^2))/(r ) =(2as ^(2))/(r )`
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Knowledge Check

  • The kinetic energy K of a particle moving along a circle of radius R depends on the distance covered a as K=as^(2) . The force acting on the particle is

    A
    `2as^(2)//R`
    B
    `2as[1+(s^(2)//R^(2))]^(1//2)`
    C
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    D
    `2aR^(2)//s`

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    A
    (a) `2a(s^2)/(R)`
    B
    (b) `2as[1+(s^2)/(R)]^(1//2)`
    C
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    D
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  • The kinetic energy of a particle moving along a circle of radius R depends on the distance covered s as T = KS2 where K is a constant. Find the force acting on the particle as a function of S -

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    D
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