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A straight wire carrying a current is...

A straight wire carrying a current is turned into a circular loop if the magnitude of magnetic moment associated with it is M then the length of the wire will be

A

`(M oi)/(4i)`

B

`sqrt(4pi i)/(M)`

C

`sqrt((4pi M)/(i))`

D

`4pi iM`

Text Solution

Verified by Experts

The correct Answer is:
C

The magnetic moment (M) of a circcular loop is
`M=iA=ixxpir^(2)`
Buut L= `2pir therefore =(L)/(2pi)`
`therefore L^(2)=(4Mpi)/(i) therefore L=sqrt(4piM)/(i)`
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