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The electon in the hydrogen atom rev...

The electon in the hydrogen atom revolves around the nucleus in an orbit of radius 0.5 A what is the equivalent magnetic moment if the frequency of revolution of the electron is `10^(10)` MHz ?

A

`"amper" // "meter"^(2) (A/m^(2))`

B

joule per tesla `(JT^(-1)`

C

amper metre

D

joule tesla

Text Solution

Verified by Experts

The correct Answer is:
C
Given : `r= 0.5 A=0.5 xx10^(-10)m`
`v=10^(10) MHZ=10^(16) Hz`
The revolving electron is equivalent to a current
and its magneitc dipole moment M= OIA =(ev) .`pir^(2)`
`=1.6 xx3.14xx0.25 xx10^(-3-20)`
`=1.256xx10^(-23)Am^(2)`
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