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Magnetic induction produced at the center of a circular loop of radius R carrying a current is 'B' The magnetic moment of the loop is

A

high susceptibility and low retentivity

B

low susceptibility and high retentivity

C

low susceptibility and low retentivity

D

high susceptibility and high retentivity

Text Solution

Verified by Experts

The correct Answer is:
B
`B=(mu_(0))/(4pi)(2pil,)/(R ) =(mu_(0)i)/(2R)`
`therefore I=(2RB)/(mu_(0))`
and A= `miR^(2)`
`therefore` Magnetic moment M=IA
`=(2RB)/(mu_(0))xxpiR^(2)=(2BpiR^(3))/(mu_(0))`
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