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A magnetising field produces a magnetic flux of `2.2 xx 10^(-5)` weber in an iron bar of cross section `0.5 cm^(2)` what is the magnetic iduction ?

A

`(1)/(300)`

B

300

C

`(1)/(600)`

D

600

Text Solution

Verified by Experts

The correct Answer is:
D

`B=(phi)/(A)=(2.2xx10^(-5))/(0.5xx10^(-4))=4.4xx10^(-1)=0.44 Wnb/m^(2)`
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