Home
Class 12
PHYSICS
A magnetising field fo 1000 A/m produc...

A magnetising field fo 1000 A/m produces a magnetics flux of `2.4 xx10^(-5)` Wb in an iron bar of cross sectional area 0.3 `cm^(2)` what is the magnetic permeability of the iron bar ?

A

weber metre `"ampere"^(-1)`

B

weber `"metre"^(-1)"ampere"^(-1)`

C

weber `"metre"^(-2)"ampere"^(-1)`

D

weber metre ampere

Text Solution

Verified by Experts

The correct Answer is:
D

A=0.3 `cm^(2) =0.3xx10^(-4) m^(2)`
Magnetic induction `B=(phi)/(A)=(2.4xx10^(-5))/(0.3xx10^(-4))`
`=0.8 Wb//m^(2)`
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|15 Videos
  • MAGNETIC EFFECTS OF ELECTRIC CURRENT

    MARVEL PUBLICATION|Exercise MCQ|195 Videos
  • OSCILLATIONS

    MARVEL PUBLICATION|Exercise MCQ|368 Videos

Similar Questions

Explore conceptually related problems

If a magnetising field of 1600 A//m produces a magnetic flux of 14xx10^(-5) Wb in an iron bar of cross-sectional area 0.2 cm^(2) . Then,

A magneting field of 1600 Am^(-1) produces a magnetic flux of 2.4xx10^(-5) wb in an iron bar of cross-sectional area 0.2cm^(2) .Calculate the permeability and susceptibility of the bar.

A magnetising field produces a magnetic flux of 2.2 xx 10^(-5) weber in an iron bar of cross section 0.5 cm^(2) what is the magnetic iduction ?

A magnetising field of 1600 Am^(-1) produces a magnetic flux 2.4 xx 10^(-5) weber in an iron bar of cross-sectional area 0.2 cm^(2) . The susceptibility of the iron bar will be

A magnetising field produces a magnetic flux of 2.2xx10^(-5) weber in an iron bar of cross section 0.5 cm^(2) . What is the magnetic induction?

A magnetising field of 5000 A//m produces a magnetic flux of 5xx10^(-5) weber in an iron rod. If the area of cross section of the rod is 0.5 cm^(2) , then the permeability of the rod will be

A magnetising field of 5000 A/m produces a magnetic flux of 5xx10^(-5) weber in an iron rod. If the area of cross section of the rod is 0.5cm^(2) , then the permeability of the rod will be

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 xx 10^(-5)Wb in a bar of iron of cross section 0.2"cm"^(2) . Then permeability of the bar is the equator