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A magnetising field of 2500 A/m produce...

A magnetising field of 2500 A/m produces a magnetic flux of `2.5 xx 10^(-5)` in an iron of cross section 0.5 `cm^(2)` weber in an iron rod of cross section `0.5 cm^(2)` what is the permeability of the iron rod in `TmA^(-1)` ?

A

`2 xx10^(-4)`

B

`2.1 xx10^(-3)`

C

`4.2 xx10^(-3)`

D

`1.05 xx10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
B
Magnetic flux `phi=BxxA`
`therefore =(phi)/(A)=(2.5xxx10^(-5))/(0.5xx10^(-4))=5xx10^(-1)=0.5 Wb/m^(2)`
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