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A iron rod is placed parallel to magn...

A iron rod is placed parallel to magnetic field of intensity `2000 A/m` The magnetic flux through the rod is `6xx10^(-4)` Wb its cross sectional area is 3 `cm^(2)` The magnetic permeability of the rod in Wb/A -m is

A

`10^(-1)`

B

`10^(-2)`

C

`10^(-3)`

D

`10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C
A=3 `cm^(2) =3xx10^(-4) m^(2) H=2000 A/m`
`B= (phi)/(A)=(6xx10^(-4))/(3xx10^(-4))=2 Wb/m^(2)`
lt `therefore mu=(B)/(H)=(2)/(2xx10^(3))=10^(-3)`
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