The magnetic moment of electron due to orbital motion is proportional to
(n= principle quantum numbers)

Options

A. `(1)/(n^(2))`
B. `(1)/(n)`
C. `n^(2)`
D. n

Answer

D

Explanation

Magnetic dipole moment of the electron due to its orbital motion is `M_(0)`
and is given by `M_(0) =(e )/(2m_(e ))xxL_(0)`
where `L_(0)` is its angular momentum
and `L_(0) -Iomega =mr^(2)xx(v)/(R )=mrv`
`before v prop n therefore L_(0) prop n therefore M_(0) prop n`