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The mgnetic flux through an air core ...

The mgnetic flux through an air core solenoid carrying a current I is `5xx10^(-6)` Wb if the length of the solenoid is 25 cm its magnetic moment will be approximately

A

`0.5 Am^(2)`

B

`0.75 Am^(2)`

C

`1 Am^(2)`

D

`2 Am^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Magnetic flux `phi =BA=(mu_(0)NI)/(L)`A
`therefore Nia=(phiL)/(mu_(0))`
The magnetic moment of the current carring coil =nIA
`=(phiL)/(mu_(0))=(5xx10^(-6)xx25xx10^(-2))/(4pixx10^(-7))=(12.5)/(4pi)=1 Am^(2)`
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